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Beliebt Rechnen >

y^{''}+400y=sec(20x),y(0)=5,y^'(0)=-5

Lösung

y^{^{''}} + 400 y = sec (20 x), y (0) = 5, y^{^{'}} (0) = - 5

Lösung

y = 5 cos (20 x) - \frac{1}{4} sin (20 x) + \frac{1}{400} ln (cos (20 x)) cos (20 x) + \frac{x sin ( 20 x )}{20}

Schritte zur Lösung

y^{''} (x) + 400 y = sec (20 x)

Solve linear ODE:

y = 5 cos (20 x) - \frac{1}{4} sin (20 x) + \frac{1}{400} ln (cos (20 x)) cos (20 x) + \frac{x sin ( 20 x )}{20}

y = 5 cos (20 x) - \frac{1}{4} sin (20 x) + \frac{1}{400} ln (cos (20 x)) cos (20 x) + \frac{x sin ( 20 x )}{20}

Graph

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