(\partial)/(\partial x)(xy-x-y+1)

Lösung

\frac{\partial}{\partial x} (x y - x - y + 1)

y - 1

Schritte zur Lösung

\frac{\partial}{\partial x} (x y - x - y + 1)

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y) - \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (1) = 0

= y - 1 - 0 + 0

Vereinfache

= y - 1

\int \frac{1}{y ^{2} - y + 1} d y

\int_{0}^{1} 7^{2 x} d x

x \to 0 lim (\frac{cos ( 3 x ) tan ( 3 x )}{x})

y^{^{'}} = y - 2 x

\int \frac{4 x ^{3}}{1 + x ^{4}} d x