integral from 1 to 4 of 3/(t^4)

Lösung

\int_{1}^{4} \frac{3}{t ^{4}} d t

\frac{63}{64}

Dezimale

0.984375

Schritte zur Lösung

\int_{1}^{4} \frac{3}{t ^{4}} d t

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{4} \frac{1}{t ^{4}} d t

Wende die Potenzregel an

= 3 [- \frac{1}{3 t ^{3}}]_{1}^{4}

Berechne die Grenzen:

\frac{21}{64}

= 3 \cdot \frac{21}{64}

Vereinfache

= \frac{63}{64}

y^{^{''}} - 2 y^{^{'}} + y = 0, y (0) = 3, y^{^{'}} (0) = 0

\int_{0}^{1} 2 π x 3 x d x

\frac{d}{d x} (8 x^{5} 2 π)

\int_{1}^{4} \frac{x ^{2} + 4}{x} d x

\frac{d}{d x} (\frac{x ^{2} + 6}{( 2 x - 7 ) ^{7}})