ty^'=3y+t^4sin(4t)

Lösung

t y^{^{'}} = 3 y + t^{4} sin (4 t)

y = - \frac{1}{4} cos (4 t) t^{3} + c_{1} t^{3}

Schritte zur Lösung

t y^{'} (t) = 3 y + t^{4} sin (4 t)

Solve linear ODE:

y = - \frac{1}{4} cos (4 t) t^{3} + c_{1} t^{3}

y = - \frac{1}{4} cos (4 t) t^{3} + c_{1} t^{3}

d er i v a t i v e f (x) = \frac{1}{x + 2}

\int \frac{4 x}{x ^{2} - 9} d x

\int 4 e^{2 x} sin (2 x) d x

\int 2 x cos (\frac{x}{3}) d x

t an g e n t f (x) = 2 x + 3, at x = 3