What is the tangent of x^2+xy-y^2=-1,(1,2) ?

The tangent of x^2+xy-y^2=-1,(1,2) is y= 4/3 x+2/3

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tangent of x^2+xy-y^2=-1,(1,2)

tangent of

x^{2} + x y - y^{2} = - 1, (1, 2)

y = \frac{4}{3} x + \frac{2}{3}

Solution steps

Find the slope of

x^{2} + x y - y^{2} = - 1 : \frac{d y}{d x} = \frac{- 2 x - y}{x - 2 y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{4}{3}

Find the line with slope m=

\frac{4}{3}

and passing through

(1, 2) : y = \frac{4}{3} x + \frac{2}{3}

y = \frac{4}{3} x + \frac{2}{3}

(x - 7) (2 x + 4)

x \to 1 lim (\frac{x}{x ^{2} + 4})

y = (4 x^{3} + 5) (x^{4} - 3 x)

n = 1 \sum \infty n + \frac{1}{n ^{2}}

\frac{d y}{d x} = 2 x

What is the tangent of x^2+xy-y^2=-1,(1,2) ?
The tangent of x^2+xy-y^2=-1,(1,2) is y= 4/3 x+2/3