What is the limit as x approaches 0 of (sin^2(6x))/7 ?

The limit as x approaches 0 of (sin^2(6x))/7 is 0

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limit as x approaches 0 of (sin^2(6x))/7

x \to 0 lim (\frac{sin ^{2} ( 6 x )}{7})

0

Solution steps

x \to 0 lim (\frac{sin ^{2} ( 6 x )}{7})

Plug in the value

x = 0

= \frac{sin ^{2} ( 6 \cdot 0 )}{7}

Simplify

\frac{sin ^{2} ( 6 \cdot 0 )}{7} : 0

= 0

in v erse l a pl a ce \frac{1}{s ( s ^{2} - 1 )}

t an g e n t f (x) = \frac{1}{x + 2}, at x = 7

d er i v a t i v e f (x) = \frac{x ^{2}}{x + 5}

\int_{4}^{9} \frac{1}{9 - x} d x

\frac{\partial}{\partial x} (3 x + 8 y + 2)

What is the limit as x approaches 0 of (sin^2(6x))/7 ?
The limit as x approaches 0 of (sin^2(6x))/7 is 0