2ty'+(4+12t^3-120t^2)y=0

Lösung

2 t y^{^{'}} + (4 + 12 t^{3} - 120 t^{2}) y = 0

y = \frac{c _{1}}{e ^{2 t^{3} - 30 t^{2}} t ^{2}}

Schritte zur Lösung

2 t y^{'} (t) + (4 + 12 t^{3} - 120 t^{2}) y = 0

Solve linear ODE:

y = \frac{c _{1}}{e ^{2 t^{3} - 30 t^{2}} t ^{2}}

y = \frac{c _{1}}{e ^{2 t^{3} - 30 t^{2}} t ^{2}}

y^{^{'}} = \frac{( - y ^{2} )}{- ( x y - x ^{3} )}

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