What is the integral from-5 to 0 of 4+sqrt(25-x^2) ?

The integral from-5 to 0 of 4+sqrt(25-x^2) is 20+(25pi)/4

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integral from-5 to 0 of 4+sqrt(25-x^2)

\int_{- 5}^{0} 4 + 25 - x^{2} d x

20 + \frac{25 π}{4}

Decimal

39.63495 \dots

Solution steps

\int_{- 5}^{0} 4 + 25 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 5}^{0} 4 d x + \int_{- 5}^{0} 25 - x^{2} d x

\int_{- 5}^{0} 4 d x = 20

\int_{- 5}^{0} 25 - x^{2} d x = \frac{25 π}{4}

= 20 + \frac{25 π}{4}

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What is the integral from-5 to 0 of 4+sqrt(25-x^2) ?
The integral from-5 to 0 of 4+sqrt(25-x^2) is 20+(25pi)/4