derivative of f(x)=x^2+8x+7

解答

\frac{d}{d x} f (x) = x^{2} + 8 x + 7

f (x) = \frac{x ^{3}}{3} + 4 x^{2} + 7 x + c_{1}

求解步骤

\frac{df}{d x} = x^{2} + 8 x + 7

若

f^{^{'}} (x) = g (x)

则

f (x) = \int g (x) d x

f (x) = \int x^{2} + 8 x + 7 d x

\int x^{2} + 8 x + 7 d x = \frac{x ^{3}}{3} + 4 x^{2} + 7 x + c_{1}

f (x) = \frac{x ^{3}}{3} + 4 x^{2} + 7 x + c_{1}

x \to 0 lim (\frac{7 x ^{5} + 5 x ^{2} + 12 x}{3 x ^{5} + 4 x})

t an g e n t x^{2} - 3 x y = 10

y^{^{'}} = \frac{sec ( y )}{( x - 3 ) ^{2}}

n = 0 \sum \infty \frac{2}{1}

\frac{\partial}{\partial x} (4 x + y)