18y^{''}+9y^'-2y=0

Lösung

18 y^{^{''}} + 9 y^{^{'}} - 2 y = 0

y = c_{1} e^{\frac{t}{6}} + c_{2} e^{- \frac{2 t}{3}}

Schritte zur Lösung

18 y^{''} (t) + 9 y^{'} (t) - 2 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{t}{6}} + c_{2} e^{- \frac{2 t}{3}}

y = c_{1} e^{\frac{t}{6}} + c_{2} e^{- \frac{2 t}{3}}

y^{^{'}} = 3 x^{2} + 1

in v erse l a pl a ce \frac{5 s - 2}{7 s ^{2} - s - 11}

x \to - \infty lim (x - 2)

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\frac{\partial}{\partial x} (y - ln (x y))