limit as t approaches+0 of (sin(7t))/t

Lösung

t \to + 0 lim (\frac{sin ( 7 t )}{t})

7

Schritte zur Lösung

t \to 0 lim (\frac{sin ( 7 t )}{t})

Wende das L'Hopital Theorem an

= t \to 0 lim (\frac{cos ( 7 t ) \cdot 7}{1})

Setze den Wert

t = 0

ein

= \frac{cos ( 7 \cdot 0 ) \cdot 7}{1}

Vereinfache

\frac{cos ( 7 \cdot 0 ) \cdot 7}{1} : 7

= 7

\int \frac{1}{x ^{3} \cdot 5 1 + \frac{1}{x}} d x

t an g e n t f (x) = - 2 x^{\frac{2}{3}} - 4, at x = 8

\int \frac{x ^{3}}{1 - x ^{8}} d x

d er i v a t i v e \frac{1 - 2 ln ( x )}{x ^{3}}

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