What is the limit as x approaches 1+of (x+1)/(x-1) ?

The limit as x approaches 1+of (x+1)/(x-1) is infinity

limit as x approaches 1+of (x+1)/(x-1)

x \to 1 + lim (\frac{x + 1}{x - 1})

\infty

Solution steps

x \to 1 + lim (\frac{x + 1}{x - 1})

\frac{x + 1}{x - 1} = (x + 1) \frac{1}{x - 1}

= x \to 1 + lim ((x + 1) \frac{1}{x - 1})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to 1 + lim (x + 1) \cdot x \to 1 + lim (\frac{1}{x - 1})

x \to 1 + lim (x + 1) = 2

x \to 1 + lim (\frac{1}{x - 1}) = \infty

= 2 \cdot \infty

Apply Infinity Property:

c \cdot \infty = \infty

= \infty

y^{^{''}} - 5 y^{^{'}} + 4 y = 0

\frac{d ^{2}}{d x ^{2}} ((6 x^{2} + 8)^{6})

n = 1 \sum \infty \frac{4}{π ^{n}}

\int x^{2} 6 x + 3 d x

d er i v a t i v e f (x) = \frac{1}{5 x + 7}

What is the limit as x approaches 1+of (x+1)/(x-1) ?
The limit as x approaches 1+of (x+1)/(x-1) is infinity