(9x+0.8x^2+0.07x^3)^'

Lösung

(9 x + 0.8 x^{2} + 0.07 x^{3})^{^{'}}

9 + 1.6 x + 0.21 x^{2}

Schritte zur Lösung

(9 x + 0.8 x^{2} + 0.07 x^{3})^{'}

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (9 x)^{^{'}} + (0.8 x^{2})^{^{'}} + (0.07 x^{3})^{^{'}}

(9 x)^{'} = 9

(0.8 x^{2})^{'} = 1.6 x

(0.07 x^{3})^{'} = 0.21 x^{2}

= 9 + 1.6 x + 0.21 x^{2}

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