(7x+2y)y^'=-2x-7y

解答

(7 x + 2 y) y^{^{'}} = - 2 x - 7 y

y = \frac{- 7 x + 45 x ^{2} + c _{1}}{2}, y = \frac{- 7 x - 45 x ^{2} + c _{1}}{2}

求解步骤

(7 x + 2 y) y^{'} (x) = - 2 x - 7 y

求解恰当方程:

y = \frac{- 7 x + 45 x ^{2} + c _{1}}{2}, y = \frac{- 7 x - 45 x ^{2} + c _{1}}{2}

y = \frac{- 7 x + 45 x ^{2} + c _{1}}{2}, y = \frac{- 7 x - 45 x ^{2} + c _{1}}{2}

\int_{0}^{1} \frac{9}{1 - x ^{2}} d x

\frac{\partial}{\partial x} (x^{4} - 5 x y + y^{4})

d er i v a t i v e f (x) = \frac{x ^{2} + 4 x + 3}{x}

y^{^{'}} tan^{- 1} (x) - y (1 + x^{2})^{- 1} = 0

\frac{d}{d x} (cos (x) + 2 sin (x) cos (x))