(\partial)/(\partial y)(-9sin(3x+yz))

解

\frac{\partial}{\partial y} (- 9 sin (3 x + yz))

- 9 cos (3 x + yz) z

解答ステップ

\frac{\partial}{\partial y} (- 9 sin (3 x + yz))

x, z

を定数として扱う

定数を除去:

(a \cdot f)^{'} = a \cdot f^{'}

= - 9 \frac{\partial}{\partial y} (sin (3 x + yz))

連鎖法則を適用:

cos (3 x + yz) \frac{\partial}{\partial y} (3 x + yz)

= cos (3 x + yz) \frac{\partial}{\partial y} (3 x + yz)

\frac{\partial}{\partial y} (3 x + yz) = z

= - 9 cos (3 x + yz) z