(\partial)/(\partial y)(-9sin(3x+yz))

Lösung

\frac{\partial}{\partial y} (- 9 sin (3 x + yz))

- 9 cos (3 x + yz) z

Schritte zur Lösung

\frac{\partial}{\partial y} (- 9 sin (3 x + yz))

Behandle

x, z

als Konstanten

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= - 9 \frac{\partial}{\partial y} (sin (3 x + yz))

Wende die Kettenregel an:

cos (3 x + yz) \frac{\partial}{\partial y} (3 x + yz)

= cos (3 x + yz) \frac{\partial}{\partial y} (3 x + yz)

\frac{\partial}{\partial y} (3 x + yz) = z

= - 9 cos (3 x + yz) z

x \to \frac{π}{8} lim (tan (24 x))

d er i v a t i v e tan (8 x)

\int_{0}^{1} 9 \frac{e ^{\frac{1}{x}}}{x ^{3}} d x

\frac{\partial}{\partial y} (8 e^{yz} cos (x yz))

s l o p e (4.8) (2.12)