(3xy^2+13y)+(3x^2y+13x)y^'=0

解答

(3 x y^{2} + 13 y) + (3 x^{2} y + 13 x) y^{^{'}} = 0

y = \frac{c _{1}}{x}

求解步骤

(3 x y^{2} + 13 y) + (3 x^{2} y + 13 x) y^{'} (x) = 0

求解线性方程:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

\int x^{2} - 1 d x

d er i v a t i v e \frac{u}{u ^{2} + 7}

\int t^{- 1} d t

\int (4 x - \frac{4}{x}) d x

d er i v a t i v e x^{3} (x - 8)^{2}