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tangent y=(36)/(x^2+2),(1,12)

解答

切线

y = \frac{36}{x ^{2} + 2}, (1, 12)

解答

y = - 8 x + 20

求解步骤

计算

y = \frac{36}{x ^{2} + 2}

的斜率:

\frac{d y}{d x} = - \frac{72 x}{( x ^{2} + 2 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 8

找到斜率 m=

- 8

且穿过

(1, 12)

的直线:

y = - 8 x + 20

y = - 8 x + 20

作图

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