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Beliebt Rechnen >

x^2y^{''}+3xy^'+2y=0,y(1)=0.2,y^'(1)=0.3

Lösung

x^{2} y^{^{''}} + 3 x y^{^{'}} + 2 y = 0, y (1) = 0.2, y^{^{'}} (1) = 0.3

Lösung

y = \frac{0.2 cos ( ln ( x ) ) + 0.5 sin ( ln ( x ) )}{x}

Schritte zur Lösung

x^{2} y^{''} (x) + 3 x y^{'} (x) + 2 y = 0

Solve linear ODE:

y = \frac{0.2 cos ( ln ( x ) ) + 0.5 sin ( ln ( x ) )}{x}

y = \frac{0.2 cos ( ln ( x ) ) + 0.5 sin ( ln ( x ) )}{x}

Graph

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