integral from 4 to infinity of e^{-x}

解答

\int_{4}^{\infty} e^{- x} d x

\frac{1}{e ^{4}}

十进制

0.01831 \dots

求解步骤

\int_{4}^{\infty} e^{- x} d x

计算不定积分:

\int e^{- x} d x = - e^{- x} + C

带入上下限计算后得:

\int_{4}^{\infty} e^{- x} d x = 0 - (- \frac{1}{e ^{4}})

= 0 - (- \frac{1}{e ^{4}})

化简

= \frac{1}{e ^{4}}

d er i v a t i v e f (x) = 2 x e^{x} csc (x)

\frac{d}{d x} (\frac{2 - x ^{2}}{3 x ^{2} + 1})

x \to - 1 + lim (\frac{x ^{2} + x}{x + 1})

\frac{d}{d x} (x^{2} \cdot x^{7})

\frac{\partial}{\partial y} (x^{4} y^{2} - x^{3} y)