tangent f(x)=(3x-5)(x+4),(2,6)

解答

切线

f (x) = (3 x - 5) (x + 4), (2, 6)

y = 19 x - 32

求解步骤

计算

f (x) = (3 x - 5) (x + 4)

的斜率:

\frac{df ( x )}{d x} = 6 x + 7

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 19

找到斜率 m=

19

且穿过

(2, 6)

的直线:

y = 19 x - 32

y = 19 x - 32

\int_{3}^{\infty} \frac{x}{x ^{2} + 1} d x

x \to - 3 lim (\frac{5 x ^{2}}{x + 3})

\frac{\partial}{\partial y} (x + y^{2})

\int 6 x \cdot csc^{2} (8 x^{2}) d x

x \to 0 + lim (e^{\frac{- 1}{x}})