斜率 g(x)=5x^2-x+7

解答

斜率

g (x) = 5 x^{2} - x + 7

10 x - 1

求解步骤

g (x) = 5 x^{2} - x + 7

要确定函数的斜率，对

5 x^{2} - x + 7

求导

\frac{d}{d x} (5 x^{2} - x + 7) = 10 x - 1

10 x - 1

\frac{d}{d x} ((8 + 7 x)^{4})

2 {d y} {d x} = \frac{21 x ^{2}}{y}

\frac{d}{d x} ((x + a) e^{2 x} + b)

\int 7 16 - 2 x d x

a re a 4 x, x^{2} - 5, [- 2.2, 0]