y^'=2x(x-2)

Lösung

y^{^{'}} = 2 x (x - 2)

y = 2 (\frac{x ^{3}}{3} - x^{2}) + c_{1}

Schritte zur Lösung

y^{'} (x) = 2 x (x - 2)

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 2 x (x - 2) d x

\int 2 x (x - 2) d x = 2 (\frac{x ^{3}}{3} - x^{2}) + c_{1}

y = 2 (\frac{x ^{3}}{3} - x^{2}) + c_{1}

n = 0 \sum \infty \frac{1 ^{n}}{n + 2}

\int_{0}^{5} \frac{1}{( 6 - 2 x ) ^{\frac{1}{3}}} d x

\int (x^{3} - 2 x)^{2} (\frac{1}{x} - 5) d x

d er i v a t i v e tan (e^{8 t}) + e^{t a n (8 t)}

t an g e n t f (x) = \frac{x}{e ^{x}}, at x = - 1