2(sin(t)y^'+cos(t)y)=cos(t)sin^3(t)

Lösung

2 (sin (t) y^{^{'}} + cos (t) y) = cos (t) sin^{3} (t)

y = \frac{sin ^{3} ( t )}{8} + \frac{c _{1}}{sin ( t )}

Schritte zur Lösung

2 (sin (t) y^{'} (t) + cos (t) y) = cos (t) sin^{3} (t)

Solve linear ODE:

y = \frac{sin ^{3} ( t )}{8} + \frac{c _{1}}{sin ( t )}

y = \frac{sin ^{3} ( t )}{8} + \frac{c _{1}}{sin ( t )}

d er i v a t i v e f (x) = e^{x^{4}}

d er i v a t i v e f (x) = 3 + 5 sin (x)

\int (3 1 + ln (x)) (x^{- 1}) d x

\int \frac{x ^{2}}{441 - x ^{2}} d x

\int p (p + 3)^{5} d p