y^{''}+y=k(e^{(-at)}-e^{(-b*t)})

Lösung

y^{^{''}} + y = k \cdot (e^{(- a \cdot t)} - e^{(- b \cdot t)})

y = c_{1} cos (t) + c_{2} sin (t) + \frac{k e ^{- a t}}{a ^{2} + 1} - \frac{k e ^{- b t}}{b ^{2} + 1}

Schritte zur Lösung

y^{''} (t) + y = k \cdot (e^{(- a \cdot t)} - e^{(- b \cdot t)})

Solve linear ODE:

y = c_{1} cos (t) + c_{2} sin (t) + \frac{k e ^{- a t}}{a ^{2} + 1} - \frac{k e ^{- b t}}{b ^{2} + 1}

y = c_{1} cos (t) + c_{2} sin (t) + \frac{k e ^{- a t}}{a ^{2} + 1} - \frac{k e ^{- b t}}{b ^{2} + 1}

\int x^{- 3} ln (x) d x

\frac{\partial}{\partial s} (e^{s + t})

\frac{\partial}{\partial x} (5 \cdot (y - 3)^{3} \cdot (x - 6))

\frac{\partial}{\partial y} (x^{8 y})

\frac{\partial}{\partial s} (t^{2})