t(dy)/(dt)=t^3+24t^3y

Lösung

t \frac{d y}{d t} = t^{3} + 24 t^{3} y

y = \frac{e ^{8 t^{3} + c_{1}}}{24} - \frac{1}{24}

Schritte zur Lösung

t \frac{d y}{d t} = t^{3} + 24 t^{3} y

Solve separable ODE:

y = \frac{e ^{8 t^{3} + c_{1}}}{24} - \frac{1}{24}

y = \frac{e ^{8 t^{3} + c_{1}}}{24} - \frac{1}{24}

\frac{\partial}{\partial x} (7 y cos (x))

n = 2 \sum \infty \frac{5}{3 ^{n}}

d er i v a t i v e - \frac{32}{( t ) ^{3}} + \frac{4}{( t ) ^{2}}

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\frac{d y}{d x} = \frac{y + 2 x y}{x}