What is the solution for x^3(dy)/(dx)+y^2=0 ?

The solution for x^3(dy)/(dx)+y^2=0 is y=-(2x^2)/(1+2c_{1)x^2}

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x^3(dy)/(dx)+y^2=0

x^{3} \frac{d y}{d x} + y^{2} = 0

y = - \frac{2 x ^{2}}{1 + 2 c _{1} x ^{2}}

Solution steps

x^{3} \frac{d y}{d x} + y^{2} = 0

Solve separable ODE:

y = - \frac{2 x ^{2}}{1 + 2 c _{1} x ^{2}}

y = - \frac{2 x ^{2}}{1 + 2 c _{1} x ^{2}}

\frac{1}{25 s ^{2} - 1}

\int t^{2} e^{t^{3}} d t

\frac{\partial}{\partial y} (ln (2 + x^{2} y^{2}))

t \cdot \frac{d y}{d t} + 14 y = \frac{1}{t}

\frac{d}{d x} (a^{x^{2}})

What is the solution for x^3(dy)/(dx)+y^2=0 ?
The solution for x^3(dy)/(dx)+y^2=0 is y=-(2x^2)/(1+2c_{1)x^2}