integral of ((x^3-6x+5)/x)

解答

\int (\frac{x ^{3} - 6 x + 5}{x}) d x

\frac{x ^{3}}{3} - 6 x + 5 ln ∣ x ∣ + C

求解步骤

\int \frac{x ^{3} - 6 x + 5}{x} d x

乘开

\frac{x ^{3} - 6 x + 5}{x} : x^{2} - 6 + \frac{5}{x}

= \int x^{2} - 6 + \frac{5}{x} d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 6 d x + \int \frac{5}{x} d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 6 d x = 6 x

\int \frac{5}{x} d x = 5 ln ∣ x ∣

= \frac{x ^{3}}{3} - 6 x + 5 ln ∣ x ∣

解答补常数

= \frac{x ^{3}}{3} - 6 x + 5 ln ∣ x ∣ + C

\frac{d}{d x} (tan (I n x))

\frac{d}{d x} (\frac{2 x + 1}{3})

\int x^{- 8} (x + 1) d x

d er i v a t i v e \frac{sin ( 8 x )}{13 x}

d er i v a t i v e 48 x (4 x^{2} + 9)^{5}