y^'=-y(1+xy^2)

Lösung

y^{^{'}} = - y (1 + x y^{2})

y = \frac{2}{- 2 x - 1 + 2 c _{1} e ^{2 x}}, y = - \frac{2}{- 2 x - 1 + 2 c _{1} e ^{2 x}}

Schritte zur Lösung

y^{'} (x) = - y (1 + x y^{2})

Solve Bernoulli ODE:

y = \frac{2}{- 2 x - 1 + 2 c _{1} e ^{2 x}}, y = - \frac{2}{- 2 x - 1 + 2 c _{1} e ^{2 x}}

y = \frac{2}{- 2 x - 1 + 2 c _{1} e ^{2 x}}, y = - \frac{2}{- 2 x - 1 + 2 c _{1} e ^{2 x}}

x \to 2 lim (\frac{x ^{3} - 2 x ^{2}}{10 x - 20})

x \to \infty lim (\frac{i}{x})

x \to 0 + lim (x + \frac{1}{x})

\int \frac{6 x}{1 + x ^{2}} d x

d er i v a t i v e (2 x - 1)^{3}