What is the tangent of f(x)=sqrt(3x+7),\at x=6 ?

The tangent of f(x)=sqrt(3x+7),\at x=6 is y= 3/10 x+16/5

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tangent of f(x)=sqrt(3x+7),\at x=6

tangent of

f (x) = 3 x + 7, at x = 6

y = \frac{3}{10} x + \frac{16}{5}

Solution steps

Find the tangent point:

(6, 5)

Find the slope of

f (x) = 3 x + 7 : \frac{df ( x )}{d x} = \frac{3}{2 3 x + 7}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{3}{10}

Find the line with slope m=

\frac{3}{10}

and passing through

(6, 5) : y = \frac{3}{10} x + \frac{16}{5}

y = \frac{3}{10} x + \frac{16}{5}

\frac{1 - 3 x}{6 + x}

f (x) = \frac{1}{( x + 1 ) ^{2}}

n = 1 \sum \infty \frac{n}{2 ^{n}}

(6, - 1), (- 3, - 10)

\frac{d}{d y} (\frac{y ^{3}}{30} + \frac{5}{2 y})

What is the tangent of f(x)=sqrt(3x+7),\at x=6 ?
The tangent of f(x)=sqrt(3x+7),\at x=6 is y= 3/10 x+16/5