integral from 0 to 4 of pi(x+1)^2

Lösung

\int_{0}^{4} π (x + 1)^{2} d x

π \frac{124}{3}

Dezimale

129.85249 \dots

Schritte zur Lösung

\int_{0}^{4} π (x + 1)^{2} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{4} (x + 1)^{2} d x

Multipliziere aus

(x + 1)^{2} : x^{2} + 2 x + 1

= π \cdot \int_{0}^{4} x^{2} + 2 x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= π (\int_{0}^{4} x^{2} d x + \int_{0}^{4} 2 x d x + \int_{0}^{4} 1 d x)

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} 2 x d x = 16

\int_{0}^{4} 1 d x = 4

= π (\frac{64}{3} + 16 + 4)

Vereinfache

π (\frac{64}{3} + 16 + 4) : π \frac{124}{3}

= π \frac{124}{3}

d er i v a t i v e f (x) = x^{3} + 2 x - 3

t an g e n t x^{2} + y^{2} = 50, (7, - 1)

x \to + (- 7) lim (- 13)

x \to \infty lim (3 x^{2})

x \to 0 + lim (x \cdot e^{(\frac{1}{x})})