derivative f(x)=x^3-27x+9

Lösung

ableitung von

f (x) = x^{3} - 27 x + 9

3 x^{2} - 27

Schritte zur Lösung

\frac{d}{d x} (x^{3} - 27 x + 9)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (27 x) + \frac{d}{d x} (9)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (27 x) = 27

\frac{d}{d x} (9) = 0

= 3 x^{2} - 27 + 0

Vereinfache

= 3 x^{2} - 27

\int \frac{5}{( 5 x + 2 ) ln ( 5 x + 2 )} d x

x \to 1 lim (x - 9)

\int (y e^{x y} + 2 x - 1) d y

y^{^{''}} + 2 y^{^{'}} + y = 2 e^{- x} + x^{3} + 2 cos (x)

\int_{1}^{\infty} \frac{x}{1 + x ^{2}} d x