(\partial)/(\partial x)(sqrt(16-x^2-4y))

解答

\frac{\partial}{\partial x} (16 - x^{2} - 4 y)

- \frac{x}{16 - x ^{2} - 4 y}

求解步骤

\frac{\partial}{\partial x} (16 - x^{2} - 4 y)

将

y

视为常数

使用连锁律:

\frac{1}{2 16 - x ^{2} - 4 y} \frac{\partial}{\partial x} (16 - x^{2} - 4 y)

= \frac{1}{2 16 - x ^{2} - 4 y} \frac{\partial}{\partial x} (16 - x^{2} - 4 y)

\frac{\partial}{\partial x} (16 - x^{2} - 4 y) = - 2 x

= \frac{1}{2 16 - x ^{2} - 4 y} (- 2 x)

化简

\frac{1}{2 16 - x ^{2} - 4 y} (- 2 x) : - \frac{x}{16 - x ^{2} - 4 y}

= - \frac{x}{16 - x ^{2} - 4 y}

x \to \infty lim (\frac{2}{x !})

l c m \frac{( csc ^{2} ( x ) )}{4}, 4 sin^{2} (x)

\frac{d ^{4}}{d x ^{4}} (cos (x))

\int v d v

x \to 10 lim (5)