derivative f(x)=x+3+4/x

Lösung

ableitung von

f (x) = x + 3 + \frac{4}{x}

- \frac{4}{x ^{2}} + 1

Schritte zur Lösung

\frac{d}{d x} (x + 3 + \frac{4}{x})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (3) + \frac{d}{d x} (\frac{4}{x})

\frac{d x}{d x} = 1

\frac{d}{d x} (3) = 0

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= 1 + 0 - \frac{4}{x ^{2}}

Vereinfache

= - \frac{4}{x ^{2}} + 1

\frac{d}{d t} (- 1)

in v erse l a pl a ce \frac{1}{( s + 1 ) ^{2} ( s ^{2} + 4 )}

a re a y = x + 2, y = \frac{1}{x + 1}, x = 2

\frac{d}{d x} (2 cot (x))

\frac{\partial}{\partial x} (2 x^{2} - 2 x y^{2})