sum from n=0 to infinity of 4n^2+4n+1

Lösung

n = 0 \sum \infty 4 n^{2} + 4 n + 1

divergiert

Schritte zur Lösung

n = 0 \sum \infty 4 n^{2} + 4 n + 1

Seriendivergenztest anwenden:

divergiert

= divergiert

a re a y = 4 x^{2}, y = x^{2} + 2

x \to 0 lim ((1 - 4 x)^{\frac{1}{x}})

x y^{^{'}} + x y = 1 - y, y (1) = 0

\frac{\partial}{\partial x} (x^{2} y^{2} (2 z + 1)^{2})

\int \frac{x ^{2}}{a ^{2} + b ^{2}} d x