derivative y=-3/(4x^4)+(24)/(5x^5)

Lösung

ableitung von

y = - \frac{3}{4 x ^{4}} + \frac{24}{5 x ^{5}}

\frac{3}{x ^{5}} - \frac{24}{x ^{6}}

Schritte zur Lösung

\frac{d}{d x} (- \frac{3}{4 x ^{4}} + \frac{24}{5 x ^{5}})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (\frac{3}{4 x ^{4}}) + \frac{d}{d x} (\frac{24}{5 x ^{5}})

\frac{d}{d x} (\frac{3}{4 x ^{4}}) = - \frac{3}{x ^{5}}

\frac{d}{d x} (\frac{24}{5 x ^{5}}) = - \frac{24}{x ^{6}}

= - (- \frac{3}{x ^{5}}) - \frac{24}{x ^{6}}

Vereinfache

= \frac{3}{x ^{5}} - \frac{24}{x ^{6}}

d er i v a t i v e (x + 1) - 1

\frac{d}{d x} (1 + 3 sin^{2} (x))

\int x^{2} x^{2} - a^{2} d x

\int_{- \infty}^{- 1} e^{- 8 t} d t

a re a y = x^{2} - 3 x, x = 0, x = 7, y = 4 x