integral from 0 to 4 of-x^2

解答

\int_{0}^{4} - x^{2} d x

- \frac{64}{3}

十进制

- 21.33333 \dots

求解步骤

\int_{0}^{4} - x^{2} d x

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{4} x^{2} d x

使用幂法则

= - [\frac{x ^{3}}{3}]_{0}^{4}

带入上下限计算后得:

\frac{64}{3}

= - \frac{64}{3}

x \to 2 lim (4 - 2 x)

\frac{d y}{d x} - y = 3 e^{x} + 12 e^{4 x}

\int x^{2} \cdot 16 - x^{2} d x

\frac{d}{d x} (\frac{x - 15}{x - 15})

d er i v a t i v e 4 x + 8