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tangent f(x)= 4/(sqrt(x)),(4,2)

解答

切线

f (x) = \frac{4}{x}, (4, 2)

解答

y = - \frac{1}{4} x + 3

求解步骤

计算

f (x) = \frac{4}{x}

的斜率:

\frac{df ( x )}{d x} = - \frac{2}{x ^{\frac{3}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{4}

找到斜率 m=

- \frac{1}{4}

且穿过

(4, 2)

的直线:

y = - \frac{1}{4} x + 3

y = - \frac{1}{4} x + 3

作图

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