(\partial)/(\partial x)(8xy^2-8x^3y)

Lösung

\frac{\partial}{\partial x} (8 x y^{2} - 8 x^{3} y)

8 y^{2} - 24 y x^{2}

Schritte zur Lösung

\frac{\partial}{\partial x} (8 x y^{2} - 8 x^{3} y)

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (8 x y^{2}) - \frac{\partial}{\partial x} (8 x^{3} y)

\frac{\partial}{\partial x} (8 x y^{2}) = 8 y^{2}

\frac{\partial}{\partial x} (8 x^{3} y) = 24 y x^{2}

= 8 y^{2} - 24 y x^{2}

\int \frac{1}{sin ^{4} ( x ) cos ^{2} ( x )} d x

\frac{\partial}{\partial x} (x^{6} + 2^{y} + x^{y})

\frac{d}{d x} (x (x^{2} + 3)^{\frac{1}{2}})

\frac{\partial}{\partial y} (x^{3} - 3 x + 3 x y^{2})

d er i v a t i v e f (x) = 7 - x^{2}