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Beliebt Rechnen >

y^{''}+6y^'+25y=0,y(0)=a,y^'(0)=b

Lösung

y^{^{''}} + 6 y^{^{'}} + 25 y = 0, y (0) = a, y^{^{'}} (0) = b

Lösung

y = e^{- 3 t} (a cos (4 t) + \frac{sin ( 4 t ) ( b + 3 a )}{4})

Schritte zur Lösung

y^{''} (t) + 6 y^{'} (t) + 25 y = 0

Solve linear ODE:

y = e^{- 3 t} (a cos (4 t) + \frac{sin ( 4 t ) ( b + 3 a )}{4})

y = e^{- 3 t} (a cos (4 t) + \frac{sin ( 4 t ) ( b + 3 a )}{4})

Graph

Beliebte Beispiele

integral from 3 to 7 of 1

\int_{3}^{7} 1 d x

integral from 0 to 6 of 1/18 x

\int_{0}^{6} \frac{1}{18} x d x

derivative of xpi

\frac{d}{d x} (x π)

inverselaplace 1/((s+3)^2)

in v erse l a pl a ce \frac{1}{( s + 3 ) ^{2}}

tangent (5x)/(sqrt(4-x^2))

t an g e n t \frac{5 x}{4 - x ^{2}}