volumeabout y=0,y=9-x^2,y=0

Lösung

volumen um

y = 0, y = 9 - x^{2}, y = 0

\frac{1296 π}{5}

Dezimale

814.30081 \dots

Schritte zur Lösung

Wenden Sie die Volumenformel an:

\int_{- 3}^{3} π - x^{2} + 9^{2} d x

Löse

\int_{- 3}^{3} π - x^{2} + 9^{2} d x : \frac{1296 π}{5}

Das Volumen des Rotationskörpers ist:

= \frac{1296 π}{5}

t an g e n t f (x) = \frac{1}{x ^{4}}, (3, \frac{1}{81})

\int \frac{\frac{4}{x ^{3}} + 2}{\frac{1}{x ^{2}} - x} d x

d er i v a t i v e f (x) = 6 x arcsin (x)

\frac{\partial}{\partial x} (arcsin (4 x yz))

t an g e n t f (x) = 18 x + 18, (1, 6)