y^{''}+15y^'+56y=0

Lösung

y^{^{''}} + 15 y^{^{'}} + 56 y = 0

y = c_{1} e^{- 7 t} + c_{2} e^{- 8 t}

Schritte zur Lösung

y^{''} (t) + 15 y^{'} (t) + 56 y = 0

Solve linear ODE:

y = c_{1} e^{- 7 t} + c_{2} e^{- 8 t}

y = c_{1} e^{- 7 t} + c_{2} e^{- 8 t}

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t^{2} y^{^{'}} + y^{2} = t y

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