What is the derivative of (5x/(x-3)) ?

The derivative of (5x/(x-3)) is -(15)/((x-3)^2)

What is the first derivative of (5x/(x-3)) ?

The first derivative of (5x/(x-3)) is -(15)/((x-3)^2)

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\frac{d}{d x} (\frac{5 x}{x - 3})

- \frac{15}{( x - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{5 x}{x - 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{x}{x - 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 5 \cdot \frac{\frac{d x}{d x} ( x - 3 ) - \frac{d}{d x} ( x - 3 ) x}{( x - 3 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x - 3) = 1

= 5 \cdot \frac{1 \cdot ( x - 3 ) - 1 \cdot x}{( x - 3 ) ^{2}}

Simplify

5 \cdot \frac{1 \cdot ( x - 3 ) - 1 \cdot x}{( x - 3 ) ^{2}} : - \frac{15}{( x - 3 ) ^{2}}

= - \frac{15}{( x - 3 ) ^{2}}

\frac{y}{12000} + 0.058 y^{^{'}} = 0.0015

x \to \infty lim (- 18 x^{4})

y = - e^{- t}

\int \frac{( x ^{2} + 2 )}{x ^{4} + 4} d x

\frac{d}{d x} (x (x^{2} + 1)^{- \frac{1}{2}})

What is the derivative of (5x/(x-3)) ?
The derivative of (5x/(x-3)) is -(15)/((x-3)^2)
What is the first derivative of (5x/(x-3)) ?
The first derivative of (5x/(x-3)) is -(15)/((x-3)^2)