y^{''}-10y^'+61y=0

Lösung

y^{^{''}} - 10 y^{^{'}} + 61 y = 0

y = e^{5 t} (c_{1} cos (6 t) + c_{2} sin (6 t))

Schritte zur Lösung

y^{''} (t) - 10 y^{'} (t) + 61 y = 0

Solve linear ODE:

y = e^{5 t} (c_{1} cos (6 t) + c_{2} sin (6 t))

y = e^{5 t} (c_{1} cos (6 t) + c_{2} sin (6 t))

in v erse l a pl a ce \frac{56 s}{s ^{2} + 196}

\frac{d y}{d x} = - 2 x tan (y), y (0) = \frac{π}{2}

\frac{d x}{d t} = x (1 - 0.0004 x)

\int_{1}^{2} 9 \frac{ln ( x )}{x ^{2}} d x

\int \frac{1}{x ( x + 1 )} d x