What is the derivative of 3x+2x^2 ?

The derivative of 3x+2x^2 is 3+4x

What is the first derivative of 3x+2x^2 ?

The first derivative of 3x+2x^2 is 3+4x

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\frac{d}{d x} (3 x + 2 x^{2})

3 + 4 x

Solution steps

\frac{d}{d x} (3 x + 2 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (2 x^{2})

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2 x^{2}) = 4 x

= 3 + 4 x

\frac{d y}{d t} = (e^{- 2 t + 3 y})

x \to 6 lim (\frac{x ^{2} - 6}{x + 4})

y = 16 - x^{2}, y = x^{2} - 2

\int \frac{19}{x ( x ^{2} + 4 ) ^{2}} d x

\int_{1}^{7} x^{2} - 4 x - 12 d x

What is the derivative of 3x+2x^2 ?
The derivative of 3x+2x^2 is 3+4x
What is the first derivative of 3x+2x^2 ?
The first derivative of 3x+2x^2 is 3+4x