(dy)/(dx)=x+4

Lösung

\frac{d y}{d x} = x + 4

y = \frac{x ^{2}}{2} + 4 x + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = x + 4

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = x + 4

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int x + 4 d x

\int x + 4 d x = \frac{x ^{2}}{2} + 4 x + c_{1}

y = \frac{x ^{2}}{2} + 4 x + c_{1}

d er i v a t i v e 30 e^{x} x

\int_{0}^{1} (u + 2) (u - 3) d u

\int \frac{x ^{2} ln ^{3} ( 1 + x ^{3} )}{1 + x ^{3}} d x

x \to 0 lim (\frac{1}{2 ^{x}})

p a r i t y sin (tan (2 x))