What is the solution for (dx)/(dt)=2+2x+t+tx ?

The solution for (dx)/(dt)=2+2x+t+tx is x=e^{2t+(t^2)/2+c_{1}}-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dx)/(dt)=2+2x+t+tx

\frac{d x}{d t} = 2 + 2 x + t + t x

x = e^{2 t + \frac{t ^{2}}{2} + c_{1}} - 1

Solution steps

\frac{d x}{d t} = 2 + 2 x + t + t x

Solve separable ODE:

x = e^{2 t + \frac{t ^{2}}{2} + c_{1}} - 1

x = e^{2 t + \frac{t ^{2}}{2} + c_{1}} - 1

\frac{\partial}{\partial x} (x^{3} + y^{2})

\frac{\partial}{\partial x} (\frac{x - 2 y ^{2}}{x ^{2} - y ^{3}})

\frac{\partial}{\partial x} (\frac{1}{x + y})

l a pl a ce t r an s f or m e^{t} sin (2 t)

\int - \frac{1}{n ^{2}} cos (n x) d x

What is the solution for (dx)/(dt)=2+2x+t+tx ?
The solution for (dx)/(dt)=2+2x+t+tx is x=e^{2t+(t^2)/2+c_{1}}-1