integral of-4/(x^3)

解答

\int - \frac{4}{x ^{3}} d x

\frac{2}{x ^{2}} + C

求解步骤

\int - \frac{4}{x ^{3}} d x

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \int \frac{1}{x ^{3}} d x

使用幂法则

= - 4 (- \frac{1}{2 x ^{2}})

化简

- 4 (- \frac{1}{2 x ^{2}}) : \frac{2}{x ^{2}}

= \frac{2}{x ^{2}}

解答补常数

= \frac{2}{x ^{2}} + C

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