y^{''}-2y^'-48y=0

Lösung

y^{^{''}} - 2 y^{^{'}} - 48 y = 0

y = c_{1} e^{8 t} + c_{2} e^{- 6 t}

Schritte zur Lösung

y^{''} (t) - 2 y^{'} (t) - 48 y = 0

Solve linear ODE:

y = c_{1} e^{8 t} + c_{2} e^{- 6 t}

y = c_{1} e^{8 t} + c_{2} e^{- 6 t}

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