(dy)/(dx)=3(y^2+1),y(pi/4)=1

解答

\frac{d y}{d x} = 3 (y^{2} + 1), y (\frac{π}{4}) = 1

y = tan (3 x - \frac{π}{2})

求解步骤

\frac{d y}{d x} = 3 (y^{2} + 1)

求解可分离方程:

y = tan (3 x - \frac{π}{2})

y = tan (3 x - \frac{π}{2})

y^{^{'}} - y = 2 t e^{2 t}

\frac{\partial}{\partial y} (2 x e^{x^{2} - y^{2}})

\int y e^{- y} d y

\frac{d}{d x} (cos^{2} (sin (4 x)))

y^{^{''}} + 5 y^{^{'}} + 6 y = 2 e^{x}, y (0) = 1, y^{^{'}} (0) = - 1