(\partial)/(\partial x)(x^2-xy+y^2)

Lösung

\frac{\partial}{\partial x} (x^{2} - x y + y^{2})

2 x - y

Schritte zur Lösung

\frac{\partial}{\partial x} (x^{2} - x y + y^{2})

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (x y) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (y^{2}) = 0

= 2 x - y + 0

Vereinfache

= 2 x - y

\frac{d}{d x} (sin (e^{x^{2}}))

\int_{1}^{e} ln (21 x) d x

x \to - 5 lim (x + 5)

\frac{\partial}{\partial z} (y^{2} z e^{z})

\frac{\partial}{\partial x} ((x^{2} + y^{2} + z^{2})^{- 0.5})